Healthcare Diagnosing or Treating Practitioners, All Other Salary in Wyoming

Ranked #30 of 43 · WY

19.2% below U.S. average
Mean annual salary $103,130 ≈ $50/hr
Median annual salary $101,280
Employment 40

Salary Distribution (10th–90th percentile)

P10 $46,880P25 $80,770 Median $101,280P75 $121,390P90 $154,780

About 80% of healthcare diagnosing or treating practitioners, all others in Wyoming earn between $46,880 and $154,780. The blue band is the middle 50% (P25–P75); the dot marks the median.

Compared to the U.S.

Wyoming
$103,130
U.S. average
$127,660

The mean healthcare diagnosing or treating practitioners, all other salary in Wyoming is $103,130, about 19.2% below the U.S. average ($127,660). That works out to roughly $50/hr at 2,080 hours per year.

Frequently Asked Questions

How much do healthcare diagnosing or treating practitioners, all other make in Wyoming?

The median healthcare diagnosing or treating practitioners, all other salary in Wyoming is $101,280 per year (mean $103,130), and about 80% earn between $46,880 and $154,780.

How much do healthcare diagnosing or treating practitioners, all other make per hour in Wyoming?

Roughly $50 per hour, based on a mean annual wage of $103,130 and 2,080 work hours per year.

Is Wyoming a high-paying state for healthcare diagnosing or treating practitioners, all other?

Wyoming ranks #30 of 43 states for healthcare diagnosing or treating practitioners, all other pay. Its mean salary of $103,130 is about 19.2% below the U.S. average of $127,660.

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